When two charged capacitors having capacitance C₁V₁ and C₂V₂ respectively are joined with the help of a wire, the common potential will be:
a) (C₁V₁ + C₂V₂) / (C₁ + C₂)
b) (C₁V₁ - C₂V₂) / (C₁ - C₂)
c) (C₁V₁C₂V₂) / (C₁V₁ + C₂V₂)
d) (C₁ + C₂) / (C₁V₁ + C₂V₂)
