Iron reacts with excess sulfuric acid to give
iron(II) sulfate. The equation for the reaction is:
Fe + H₂SO4 → FeSO4 + H₂
5 g of iron gives 13.6 g of iron(II) sulfate.
a Using excess acid, how much iron(II) sulfate
can be obtained from:
i 10 g of iron?
ii 1 g of iron?
b How much iron will be needed to make 136 g
of iron(II) sulfate?
c A 10 g sample of impure iron(II) sulfate
contains 8 g of iron(II) sulfate. Calculate the
percentage purity of the iron(II) sulfate.
