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29-12-2023
Chemistry

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EMF of the following cell is 0.634 volt at 298 K. ltbr> Pt∣Hg₂)(1atm)H⁺(aq)||KCl(1N)|Hg₂Cl₂(s)|Hg
Calculate pH of the anode compartment.
[Given: E°Cₗ⁻|Hg₂Cl₂|Hg = 0.28 V and 2.303Rt/F=0.059]

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