havaxd havaxd
  • 29-12-2023
  • Mathematics
contestada

Why is:

[tex]y = \frac{x}{z} \cdot tan(a) - 1 + \frac{1}{tan(a)}[/tex]

the same as:

[tex]y = \frac{x}{\tan(a) \cdot z}[/tex]

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