Question

Laplace transforms to solve the initial value problem: y'' - 2y' + 5y = 6e(-t); y(0) = 3; y'(0) = 5

A) y(t) = 3e(2t) + 2e(-t)
B) y(t) = 3e(-2t) + 2eᵗ
C) y(t) = 3e(-t) + 2e(2t)
D) y(t) = 3eᵗ + 2e(-2t)