Na2S2O3 is a reducing agent that is used to convert the hazard iodine la to non hazardous Nal according to the equation below, 2 Na2S2O3 +12 — - Na S406+ 2 Nal If 20.0mL of 1.0M Na2S2O3 solution was reacted with 2.5381g of , what is the limiting reactant in this reaction? There is no limiting reactant Na 520 12 Na 540 Question 20 5 pts Na2S2O3 is a reducing agent that is used to convert the hazardous iodine iz to non hazardous Nal according to the equation below. 2 Na2S2O3 +12 -Na2S40. +2 Nal If 20.0mL of 1.0M Na2S2O3 solution was reacted with 2.53818 of 12 (molar mass = 253.81 g/mol) what is the theoretical yield of Nal (molar mass - 149.89 g/mol) from this reaction? 3.9988 -43798 2.7318 2.9988
