In an acid-base standardization of the above prepared solution, 23.46 mL of the NaOH stock solution are needed to neutralize a 25.00 mL sample of 0.116 HCl solution. b. Write the chemical equation for this reaction. Using the titration values, what is the calculated molarity of the NaOH stock solution? c. d. Why would (or should) you expect the answer for parts a and c to be different? e. What is the molarity of the OH in the standardized NaOH solution?
