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Solve this system of equations using a matrix inverse.
z+y=10
2z-z=9
y-3x = -5
If A is the coefficient matrix of the above system of equations and A¹ =
R₂ are
and the elements Rs are
R₂, then the elements of Rare [1,2,-2, the elements of
[RS]
The solution of this system is (x, y, z)=(3,7,4).
