Consider the following balanced equation:
6HCl(aq) + 2Al(s) → 3H2(g) + 2AlCl3(s)
If 17.3 moles of HCl(aq) and 7.07 moles of Al(s) are allowed to react, and the percent yield is 71.8%, how many moles of AlCl3(s) will actually be produced?