60 passengers have boarding passes for a plane with 60 seats. The first k (k < 10) passengers lose their boarding passes, and are instructed to just sit anywhere, so they randomly pick seats on the plane. The remaining passengers board the plane one at a time, each one sitting in his or her assigned seat if it is unoccupied, otherwise randomly choosing an empty seat. For each of the last five passengers P56, P57, P58, P59, and P60, determine the probability that he or she will end up in his or her assigned seat. Partial Answer: P56 = 5/(k + 5).
