The following set of reactions show
burning hydrogen and the reverse
process, electrolysis of water. What is
the missing change in enthalpy? Only
put in the numerical value. (The bond
energy of H-H is 432 kJ/mol was used
in the first equation. Other bond
energies are on this form, IF you need
it.)
_2_H₂ + _1_0₂_2_H₂O
_2_H₂O →_2_H₂ +_1_O₂
ΔΗrxn=-498 kJ/mol
ΔΗrxn= ??? kJ/mol
