The solution of a system of linear equations is (2,−4). One equation in the system is 2x+y=0. Which best explains how you could find a second equation for the system? Responses Find the line parallel to 2x+y=0 through (2,−4). Find the line parallel to 2 x plus y is equal to 0 through . Find the line perpendicular to 2x+y=0 through (2,−4). Find the line perpendicular to , 2 x plus y is equal to 0 through . Write any equation in standard form that has a slope of −2. Write any equation in standard form that has a slope of negative 2. Rewrite 2x+y=0 so it is in slope-intercept form, then change the slope to −4. Rewrite 2 x plus y is equal to 0 so it is in slope-intercept form, then change the slope to negative 4. Question 2 Which equation could be in the system with 2x+y=0? Responses −2x+y=8negative 2 x plus y is equal to 8 x−2y=10 x−4y=2 2x+y=4
