The radius of a cone is increasing at a constant rate of 2 feet per second. The volume remains a constant 373 cubic feet. At the instant when the height of the cone is 55 feet, what is the rate of change of the height? The volume of a cone can be found with the equation V=\frac{1}{3}\pi r^2 h. V=
3
1
πr
2
h. Round your answer to three decimal places
