If 136 g of BaCl₂ (FW 208.23 g/mol) is added to a solution containing 95.0 g of Na₃PO₄ (FW 163.94 g/mol), what mass, in g, of Ba₃(PO₄)₂ (FW 601.92 g/mol) precipitate will be formed? The balanced equation is
3 BaCl₂(aq) + 2 Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6 NaCl(aq)
