The reaction below describes all chemical changes occurring in a galvanic cell. The sold metals (Cr and Cu) represent electrodes submerged in the solutions. Use thise cell, and the list of common polyatomic ions below it (picture attached), to answer questions 13-16.
[tex]Cr(s) + CuSO_{4}(aq) = Cu(s) + Cr_{2}(SO_{4})_{3}(aq)[/tex]
13. What is the net ionic equation for the reactions taking place in the galvanic cell above?
- [tex]Cr(s) + CuSo_{4}(aq) = Cu(s) + Cr_{2}(SO_{4})_{3}(aq)[/tex]
- [tex]Cr(s) = Cu(s)[/tex]
- [tex]Cr(s) + Cu^{+2}(aq) + SO_{4}^{-2}(aq) = Cu(s) + Cr^{+3}(aq) + SO_{4}^{-2}(aq)[/tex]
- [tex]Cr(s) + Cu^{+2}(aq) = Cu(s) + Cr^{+3}(aq)[/tex]
14. What is the oxidation half reaction for the reactions taking place in the galvanic cell above?
- [tex]Cu^{+2}(aq)+2e^{-1} = Cu(s)[/tex]
- [tex]Cr(s) + Cu^{+2}(aq) = Cu(s) + Cr^{+3}[/tex]
- [tex]Cr(s) = Cr^{+3} + 3e^{-1}[/tex]
- [tex]Cr(s) + CuSO_{4}(aq) = Cu(s) + Cr_{2}(SO_{4})_{3}(aq)[/tex]
15. What is the reduction half reaction for the reactions taking place in the galvanic cell above?
- [tex]Cu^{+2}(aq) + 2e^{-1} = Cu(s)[/tex]
- [tex]Cr(s) + Cu^{+2}(aq) = Cu(s) + Cr^{+3}[/tex]
- [tex]Cr(s) = Cr^{+3} + 3e^{-1}[/tex]
- [tex]Cr(s) + CuSO_{4}(aq) = Cu(s) + Cr_{2}(SO_{4})_{3}(aq)[/tex]
16. Balancing the electrons produced and used in the redox reaction taking place in the galvanic cell above, what is the balanced net ionic reaction?
- [tex]3Cu^{+2}(aq) + 6e^{-1} = 3Cu(s)[/tex]
- [tex]2Cr(s) + 3Cu^{+2}(aq) = 3Cu(s) + 2Cr^{+3}[/tex]
- [tex]2Cr(s) = 2Cr^{+3} + 6e^{-1}[/tex]
- [tex]Cr(s) + CuSO_{4}(aq) = Cu(s) + Cr_{2}(SO_{4})_{3}(aq)[/tex]
- [tex]Cr(s) + Cu^{+2}(a) + SO_{4}^{-2}(aq) = Cu(s) + Cr^{+3} + SO_{4}^{-2}(aq)[/tex]
- [tex]3Cr(s) + 2u^{+2}(aq) = 2Cu(s) + 3Cr^{+3}[/tex]
17. Using the balanced net ionic equation, what is the balanced reaction equation for the redox reaction taking place in the galvanic cell above?
- [tex]2Cr(s) + 3CuSO_{4}(aq) = 3Cu(s) + Cr_{2}(SO_{4})_{3}(aq)[/tex]
- [tex]2Cr(s) + 3CuSO_{4}(aq) = 3Cu(s) + 2Cr_{2}(SO_{4})_{3}(aq)[/tex]
- [tex]3Cr(s) + 2CuSO_{4}(aq) = 2Cu(s) + 3Cr_{2}(SO_{4})_{3}(aq)[/tex]
If you can help and please explain, that would be great! I'll be marking the best answer Brainliest. Have a great day! :)