8) Aluminum and chlorine combine to form aluminum chloride.
2Al(s)+3Cl2(g)-2AlCl3(s)
a. How many moles of Cl2 are needed to react with 2.50 moles of Al?
b. How many grams of AlCl3 are produced when 37.7 g of Al reacts?
c. When 13.5 g of Al reacts with 8.00 g of Cl2, how many grams of AlCl3 can form?
d. If 45.0 g of Al and 62.0 g Cl2 are mixed, and 66.5 g of AlCl3 is actually obtained, what is the percent Yield of AlCl3 for the reaction?
