Question

hello everyone! Can anybody help me out with this problem? I don't need a big explanation just the answer and a brief explanation on how you got it :)

Answer 1

Given the table between (x) and (y)

The constant of variation (k) is given by:

$k=\frac{y}{x}$

As shown, from the table

When x= -2, y = -4

$k=\frac{-4}{-2}=2$

when x = 1, y = 2

$k=\frac{2}{1}=2$

when x = 6, y = 12

$k=\frac{12}{6}=2$

so, the answer will be k = 2