Question

Give the equation of the circle centered at the origin and passing through the point (9,0).

Answer 1

EXPLANATION

Let's see the facts:

Center of the circle---> Origin = (0,0)

Pass through point ---> (9,0)

As we can see in graph, the radius of the circle is equal to r=9

With this given information, the equation standard form will be:

(x-h)^2 + (y-k)^2 = r^2

With value of h=0 and k=0, equation will be:

x^2+y^2 = 9^2

[ANSWER] x^2 + y^2 = 81