Jim collects toy cars. He started his collection with 20 toy cars, and each
month he gains 6 more toy cars.
Recursive: f(n) = f(n-1) + 6, f(1) = 20
Explicit: f(n) = 20 + 6n
In this example, the letter n is our variable that represents our input value of
which month we are in. In this example, f(n) is representing our output value
of how many toy cars Jim has. As this is an ARITHMETIC sequence, we have
a common difference that is represented in our recursive equation by adding
6, and in our explicit equation by multiplying our variable by our common
difference of 6. Note that arithmetic sequences are built on repeated
addition, which can be represented in your explicit equation with
multiplication.
