5. Using the figure shown below, Compute the resultant electric field (magnitude and direction) at (a) point a, midway between the charges, and (b) point b, 4.0 cm to the left of q1 9₁ = +12 nC -4.0 cm- -5.0 cm- - Perpendicular bisector 92=-12 nC -5.0 cm- ➜ answer(a)E. E-432X10 N/C (h)E. -
674X104N/C F-55X10³ NIC
