Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor.
NO2- + 6e- -> NH4+ (E0 = +0.34 volts)
O2 + 4e- -> 2H2O (E0 = +0.82 volts)
If you balance and combine the reactions so that 217 moles of NH4+ are oxidized to NO2-, how many moles of H+ will be produced?
